(2x^2+5x)+(10x+3)=180

Solution for (2x^2+5x)+(10x+3)=180 equation:

(2x^2+5x)+(10x+3)=180

We move all terms to the left:

(2x^2+5x)+(10x+3)-(180)=0

We get rid of parentheses

2x^2+5x+10x+3-180=0

We add all the numbers together, and all the variables

2x^2+15x-177=0

a = 2; b = 15; c = -177;
Δ = b2-4ac
Δ = 152-4·2·(-177)
Δ = 1641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{1641}}{2*2}=\frac{-15-\sqrt{1641}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{1641}}{2*2}=\frac{-15+\sqrt{1641}}{4}
$